ASVAB Math Knowledge Practice Test 272210

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6a - 3a = -4a + 5x + 7 for a in terms of x.

\(\frac{5}{13}\)x + \(\frac{5}{13}\)
1\(\frac{5}{6}\)x + \(\frac{1}{2}\)
-4x - 3\(\frac{1}{2}\)
-\(\frac{1}{2}\)x + 1\(\frac{3}{4}\)