When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c - 3c = -6c - 8z - 7 for c in terms of z.
| -2\(\frac{1}{2}\)z - 3\(\frac{1}{2}\) | |
| 5z - 6 | |
| -1\(\frac{1}{14}\)z + \(\frac{1}{14}\) | |
| -\(\frac{5}{13}\)z - \(\frac{7}{13}\) |