When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c - 8c = 3c - 9z + 2 for c in terms of z.
| -\(\frac{1}{3}\)z + \(\frac{2}{3}\) | |
| 7z + 9 | |
| \(\frac{9}{10}\)z + \(\frac{3}{5}\) | |
| \(\frac{8}{13}\)z + \(\frac{3}{13}\) |