ASVAB Math Knowledge Practice Test 278202

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 5a - 4a = 4a - 4y - 3 for a in terms of y.

y - 3
-\(\frac{1}{5}\)y + \(\frac{1}{15}\)
-1\(\frac{2}{3}\)y + 2\(\frac{2}{3}\)
-10y + 5