ASVAB Math Knowledge Practice Test 278416

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -2b + 5b = -4b - 4z + 3 for b in terms of z.

-\(\frac{8}{9}\)z + \(\frac{4}{9}\)
3\(\frac{1}{4}\)z + 1
-4\(\frac{1}{2}\)z + 1\(\frac{1}{2}\)
2z + 1\(\frac{1}{3}\)