ASVAB Math Knowledge Practice Test 278428

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 5c - c = 2c - 8y - 1 for c in terms of y.

\(\frac{1}{2}\)y - \(\frac{2}{7}\)
-\(\frac{2}{3}\)y + \(\frac{1}{3}\)
3y - 4
-2\(\frac{1}{3}\)y - \(\frac{1}{3}\)