When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6b + 8b = b - 4z + 4 for b in terms of z.
| -2\(\frac{2}{5}\)z + \(\frac{4}{5}\) | |
| z - 4 | |
| -\(\frac{1}{4}\)z - \(\frac{1}{2}\) | |
| \(\frac{4}{9}\)z - \(\frac{7}{9}\) |