ASVAB Math Knowledge Practice Test 280323 Results

Your Results Global Average
Questions 5 5
Correct 0 2.96
Score 0% 59%

Review

1

Solve 4a - 8a = -2a - y - 6 for a in terms of y.

34% Answer Correctly
\(\frac{1}{2}\)y - 3
y + 2
y + 1
1\(\frac{1}{6}\)y - 1

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

4a - 8y = -2a - y - 6
4a = -2a - y - 6 + 8y
4a + 2a = -y - 6 + 8y
6a = 7y - 6
a = \( \frac{7y - 6}{6} \)
a = \( \frac{7y}{6} \) + \( \frac{-6}{6} \)
a = 1\(\frac{1}{6}\)y - 1


2

The dimensions of this cube are height (h) = 2, length (l) = 9, and width (w) = 3. What is the surface area?

51% Answer Correctly
46
34
102
450

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 9 x 3) + (2 x 3 x 2) + (2 x 9 x 2)
sa = (54) + (12) + (36)
sa = 102


3

The endpoints of this line segment are at (-2, -5) and (2, -3). What is the slope of this line?

46% Answer Correctly
\(\frac{1}{2}\)
-\(\frac{1}{2}\)
-3
2

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -5) and (2, -3) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-3.0) - (-5.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)
m = \(\frac{1}{2}\)


4

A(n) __________ is two expressions separated by an equal sign.

77% Answer Correctly

problem

equation

formula

expression


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


5

To multiply binomials, use the FOIL method. Which of the following is not a part of the FOIL method?

84% Answer Correctly

First

Inside

Last

Odd


Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses.