When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -5c - 3c = 4c - 5y + 5 for c in terms of y.
| y + \(\frac{1}{12}\) | |
| \(\frac{2}{9}\)y - \(\frac{5}{9}\) | |
| -\(\frac{1}{3}\)y - 1 | |
| \(\frac{5}{6}\)y - \(\frac{1}{2}\) |