When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + c = -6c + 6z + 1 for c in terms of z.
| -1\(\frac{2}{11}\)z - \(\frac{5}{11}\) | |
| \(\frac{1}{2}\)z + \(\frac{1}{10}\) | |
| -5\(\frac{2}{3}\)z - 2\(\frac{1}{3}\) | |
| -1\(\frac{1}{5}\)z - \(\frac{1}{5}\) |