ASVAB Math Knowledge Practice Test 28136 Results

Your Results Global Average
Questions 5 5
Correct 0 3.56
Score 0% 71%

Review

1

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

91% Answer Correctly

pairs

addition

division

exponents


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


2

A coordinate grid is composed of which of the following?

91% Answer Correctly

x-axis

y-axis

origin

all of these


Solution

The coordinate grid is composed of a horizontal x-axis and a vertical y-axis. The center of the grid, where the x-axis and y-axis meet, is called the origin.


3

What is 9a - 4a?

80% Answer Correctly
5
36a
5a
a2

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

9a - 4a = 5a


4

If the area of this square is 4, what is the length of one of the diagonals?

68% Answer Correctly
6\( \sqrt{2} \)
3\( \sqrt{2} \)
\( \sqrt{2} \)
2\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)


5

The formula for the area of a circle is which of the following?

24% Answer Correctly

c = π d2

c = π d

c = π r2

c = π r


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.