ASVAB Math Knowledge Practice Test 282293 Results

Your Results Global Average
Questions 5 5
Correct 0 3.39
Score 0% 68%

Review

1

On this circle, line segment AB is the:

70% Answer Correctly

diameter

chord

radius

circumference


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


2

The dimensions of this cylinder are height (h) = 5 and radius (r) = 1. What is the volume?

62% Answer Correctly
25π
50π
288π

Solution

The volume of a cylinder is πr2h:

v = πr2h
v = π(12 x 5)
v = 5π


3

Simplify 6a x 2b.

85% Answer Correctly
12\( \frac{b}{a} \)
12a2b2
12ab
8ab

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

6a x 2b = (6 x 2) (a x b) = 12ab


4

If the area of this square is 4, what is the length of one of the diagonals?

68% Answer Correctly
2\( \sqrt{2} \)
5\( \sqrt{2} \)
4\( \sqrt{2} \)
\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)


5

The dimensions of this cube are height (h) = 5, length (l) = 8, and width (w) = 6. What is the surface area?

51% Answer Correctly
182
236
382
190

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 8 x 6) + (2 x 6 x 5) + (2 x 8 x 5)
sa = (96) + (60) + (80)
sa = 236