| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.39 |
| Score | 0% | 68% |
On this circle, line segment AB is the:
diameter |
|
chord |
|
radius |
|
circumference |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
The dimensions of this cylinder are height (h) = 5 and radius (r) = 1. What is the volume?
| 25π | |
| 50π | |
| 5π | |
| 288π |
The volume of a cylinder is πr2h:
v = πr2h
v = π(12 x 5)
v = 5π
Simplify 6a x 2b.
| 12\( \frac{b}{a} \) | |
| 12a2b2 | |
| 12ab | |
| 8ab |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
6a x 2b = (6 x 2) (a x b) = 12ab
If the area of this square is 4, what is the length of one of the diagonals?
| 2\( \sqrt{2} \) | |
| 5\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| \( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)
The dimensions of this cube are height (h) = 5, length (l) = 8, and width (w) = 6. What is the surface area?
| 182 | |
| 236 | |
| 382 | |
| 190 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 8 x 6) + (2 x 6 x 5) + (2 x 8 x 5)
sa = (96) + (60) + (80)
sa = 236