ASVAB Math Knowledge Practice Test 282752

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6c - 3c = c - 9z + 3 for c in terms of z.

\(\frac{6}{7}\)z - \(\frac{3}{7}\)
3z - 5
-5\(\frac{1}{2}\)z - 4
z - 1