| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.45 |
| Score | 0% | 69% |
If the area of this square is 16, what is the length of one of the diagonals?
| 4\( \sqrt{2} \) | |
| 7\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) | |
| \( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{16} \) = 4
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 42 + 42
c2 = 32
c = \( \sqrt{32} \) = \( \sqrt{16 x 2} \) = \( \sqrt{16} \) \( \sqrt{2} \)
c = 4\( \sqrt{2} \)
Which of the following statements about math operations is incorrect?
you can subtract monomials that have the same variable and the same exponent |
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you can add monomials that have the same variable and the same exponent |
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all of these statements are correct |
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you can multiply monomials that have different variables and different exponents |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
This diagram represents two parallel lines with a transversal. If x° = 147, what is the value of b°?
| 33 | |
| 140 | |
| 147 | |
| 164 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with x° = 147, the value of b° is 147.
If side a = 6, side b = 5, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{61} \) | |
| \( \sqrt{68} \) | |
| \( \sqrt{85} \) | |
| \( \sqrt{50} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 62 + 52
c2 = 36 + 25
c2 = 61
c = \( \sqrt{61} \)
If angle a = 62° and angle b = 60° what is the length of angle c?
| 58° | |
| 77° | |
| 61° | |
| 75° |
The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 62° - 60° = 58°