When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve c - 8c = -2c - 6x + 4 for c in terms of x.
| 2\(\frac{1}{5}\)x + 1\(\frac{4}{5}\) | |
| \(\frac{2}{3}\)x + 1\(\frac{1}{3}\) | |
| -\(\frac{7}{11}\)x + \(\frac{6}{11}\) | |
| \(\frac{2}{3}\)x + \(\frac{1}{3}\) |