ASVAB Math Knowledge Practice Test 28401

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6a + a = 2a - 3y + 3 for a in terms of y.

\(\frac{1}{2}\)y - \(\frac{3}{8}\)
6y - 7
-\(\frac{4}{5}\)y - 1\(\frac{2}{5}\)
1\(\frac{4}{11}\)y + \(\frac{7}{11}\)