| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.04 |
| Score | 0% | 61% |
Solve for c:
6c + 3 > 2 - 6c
| c > -2\(\frac{1}{4}\) | |
| c > -1 | |
| c > -\(\frac{1}{12}\) | |
| c > -1\(\frac{1}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
6c + 3 > 2 - 6c
6c > 2 - 6c - 3
6c + 6c > 2 - 3
12c > -1
c > \( \frac{-1}{12} \)
c > -\(\frac{1}{12}\)
Solve for x:
9x + 5 = \( \frac{x}{-3} \)
| \(\frac{6}{23}\) | |
| -1\(\frac{8}{41}\) | |
| -\(\frac{15}{28}\) | |
| -\(\frac{16}{31}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
9x + 5 = \( \frac{x}{-3} \)
-3 x (9x + 5) = x
(-3 x 9x) + (-3 x 5) = x
-27x - 15 = x
-27x - 15 - x = 0
-27x - x = 15
-28x = 15
x = \( \frac{15}{-28} \)
x = -\(\frac{15}{28}\)
If angle a = 35° and angle b = 68° what is the length of angle d?
| 145° | |
| 128° | |
| 127° | |
| 124° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 35° - 68° = 77°
So, d° = 68° + 77° = 145°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 35° = 145°
What is 2a - 8a?
| -6a2 | |
| 16a | |
| -6a | |
| -6 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
2a - 8a = -6a
A trapezoid is a quadrilateral with one set of __________ sides.
equal angle |
|
right angle |
|
equal length |
|
parallel |
A trapezoid is a quadrilateral with one set of parallel sides.