ASVAB Math Knowledge Practice Test 284227

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 8b + 3b = 2b - 6y - 3 for b in terms of y.

-1\(\frac{1}{2}\)y - \(\frac{1}{2}\)
14y + 6
5\(\frac{1}{2}\)y + 3
\(\frac{1}{2}\)y - \(\frac{5}{8}\)