When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c - 5c = c - 6x - 1 for c in terms of x.
| -x - 1 | |
| -3\(\frac{1}{5}\)x + \(\frac{2}{5}\) | |
| x - \(\frac{6}{7}\) | |
| x + 2 |