When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 4c = 4c + 5z + 6 for c in terms of z.
| -\(\frac{1}{10}\)z - \(\frac{9}{10}\) | |
| 2\(\frac{2}{3}\)z + \(\frac{2}{3}\) | |
| -\(\frac{1}{3}\)z + 1 | |
| -z - 6 |