ASVAB Math Knowledge Practice Test 284881

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6a + 6a = -5a + 3y - 1 for a in terms of y.

y + 1
\(\frac{6}{11}\)y + \(\frac{1}{11}\)
-\(\frac{3}{11}\)y - \(\frac{1}{11}\)
-\(\frac{3}{11}\)y + \(\frac{7}{11}\)