When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5b - b = -5b - 3z + 1 for b in terms of z.
| \(\frac{1}{4}\)z - \(\frac{5}{16}\) | |
| -\(\frac{1}{5}\)z + \(\frac{1}{10}\) | |
| -\(\frac{1}{6}\)z + \(\frac{1}{2}\) | |
| \(\frac{4}{7}\)z + \(\frac{1}{14}\) |