ASVAB Math Knowledge Practice Test 290219 Results

Your Results Global Average
Questions 5 5
Correct 0 3.05
Score 0% 61%

Review

1

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

60% Answer Correctly

supplementary, vertical

obtuse, acute

vertical, supplementary

acute, obtuse


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


2

This diagram represents two parallel lines with a transversal. If b° = 151, what is the value of z°?

73% Answer Correctly
144
29
160
18

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with b° = 151, the value of z° is 29.


3

Solve for z:
-8z + 4 > 2 + 3z

55% Answer Correctly
z > -\(\frac{3}{8}\)
z > -4
z > \(\frac{2}{11}\)
z > 5

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

-8z + 4 > 2 + 3z
-8z > 2 + 3z - 4
-8z - 3z > 2 - 4
-11z > -2
z > \( \frac{-2}{-11} \)
z > \(\frac{2}{11}\)


4

If the base of this triangle is 9 and the height is 3, what is the area?

58% Answer Correctly
112\(\frac{1}{2}\)
98
13\(\frac{1}{2}\)
60

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 9 x 3 = \( \frac{27}{2} \) = 13\(\frac{1}{2}\)


5

Solve for z:
6z - 7 = 8 - z

59% Answer Correctly
-1
2\(\frac{1}{7}\)
-\(\frac{1}{5}\)
-\(\frac{4}{9}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

6z - 7 = 8 - z
6z = 8 - z + 7
6z + z = 8 + 7
7z = 15
z = \( \frac{15}{7} \)
z = 2\(\frac{1}{7}\)