| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.05 |
| Score | 0% | 61% |
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
supplementary, vertical |
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obtuse, acute |
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vertical, supplementary |
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acute, obtuse |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
This diagram represents two parallel lines with a transversal. If b° = 151, what is the value of z°?
| 144 | |
| 29 | |
| 160 | |
| 18 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with b° = 151, the value of z° is 29.
Solve for z:
-8z + 4 > 2 + 3z
| z > -\(\frac{3}{8}\) | |
| z > -4 | |
| z > \(\frac{2}{11}\) | |
| z > 5 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-8z + 4 > 2 + 3z
-8z > 2 + 3z - 4
-8z - 3z > 2 - 4
-11z > -2
z > \( \frac{-2}{-11} \)
z > \(\frac{2}{11}\)
If the base of this triangle is 9 and the height is 3, what is the area?
| 112\(\frac{1}{2}\) | |
| 98 | |
| 13\(\frac{1}{2}\) | |
| 60 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 9 x 3 = \( \frac{27}{2} \) = 13\(\frac{1}{2}\)
Solve for z:
6z - 7 = 8 - z
| -1 | |
| 2\(\frac{1}{7}\) | |
| -\(\frac{1}{5}\) | |
| -\(\frac{4}{9}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
6z - 7 = 8 - z
6z = 8 - z + 7
6z + z = 8 + 7
7z = 15
z = \( \frac{15}{7} \)
z = 2\(\frac{1}{7}\)