When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 2c = 4c - 9x - 6 for c in terms of x.
| -1\(\frac{2}{3}\)x - 1\(\frac{2}{3}\) | |
| -\(\frac{4}{5}\)x - \(\frac{3}{10}\) | |
| -\(\frac{5}{12}\)x - \(\frac{1}{3}\) | |
| -5\(\frac{1}{2}\)x - 3 |