ASVAB Math Knowledge Practice Test 292096

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6c - 2c = -9c - 5z - 4 for c in terms of z.

-14z + 3
-z - 1\(\frac{1}{3}\)
-\(\frac{1}{5}\)z + \(\frac{4}{5}\)
\(\frac{5}{6}\)z + \(\frac{1}{6}\)