ASVAB Math Knowledge Practice Test 294035

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2c + 8c = 4c - 7z - 3 for c in terms of z.

z + 4\(\frac{1}{2}\)
-2z - 2\(\frac{2}{3}\)
7\(\frac{1}{2}\)z + 1\(\frac{1}{2}\)
6\(\frac{1}{2}\)z + 4\(\frac{1}{2}\)