When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 4c = -4c + 5x - 8 for c in terms of x.
| -3\(\frac{2}{3}\)x - 1\(\frac{1}{3}\) | |
| -1\(\frac{1}{3}\)x - \(\frac{1}{6}\) | |
| -\(\frac{11}{15}\)x + \(\frac{8}{15}\) | |
| \(\frac{1}{10}\)x - \(\frac{4}{5}\) |