| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.21 |
| Score | 0% | 64% |
If BD = 27 and AD = 28, AB = ?
| 10 | |
| 1 | |
| 12 | |
| 5 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDIf angle a = 60° and angle b = 36° what is the length of angle d?
| 118° | |
| 115° | |
| 133° | |
| 120° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 60° - 36° = 84°
So, d° = 36° + 84° = 120°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 60° = 120°
What is 8a + 7a?
| 15a | |
| a2 | |
| 56a | |
| 15 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
8a + 7a = 15a
The dimensions of this cylinder are height (h) = 2 and radius (r) = 9. What is the volume?
| 8π | |
| 162π | |
| 150π | |
| 75π |
The volume of a cylinder is πr2h:
v = πr2h
v = π(92 x 2)
v = 162π
Solve for b:
b - 1 = \( \frac{b}{-6} \)
| 1\(\frac{5}{11}\) | |
| 1\(\frac{9}{26}\) | |
| -\(\frac{35}{36}\) | |
| \(\frac{6}{7}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
b - 1 = \( \frac{b}{-6} \)
-6 x (b - 1) = b
(-6 x b) + (-6 x -1) = b
-6b + 6 = b
-6b + 6 - b = 0
-6b - b = -6
-7b = -6
b = \( \frac{-6}{-7} \)
b = \(\frac{6}{7}\)