ASVAB Math Knowledge Practice Test 297680 Results

	Your Results	Global Average
Questions	5	5
Correct	0	2.73
Score	0%	55%

Review

A quadrilateral is a shape with __________ sides.

91% Answer Correctly

	3
	2
	5
	4

Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.

If the length of AB equals the length of BD, point B __________ this line segment.

46% Answer Correctly

	bisects
	midpoints
	intersects
	trisects

Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.

The endpoints of this line segment are at (-2, -3) and (2, 5). What is the slope-intercept equation for this line?

41% Answer Correctly

	y = -2\(\frac{1}{2}\)x + 2
	y = 2x + 1
	y = -1\(\frac{1}{2}\)x + 2
	y = 2\(\frac{1}{2}\)x + 2

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -3) and (2, 5) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(5.0) - (-3.0)}{(2) - (-2)} \) = \( \frac{8}{4} \)
m = 2

Plugging these values into the slope-intercept equation:

y = 2x + 1

The dimensions of this cylinder are height (h) = 1 and radius (r) = 6. What is the surface area?

48% Answer Correctly

	84π
	30π
	154π
	88π

Solution

The surface area of a cylinder is 2πr² + 2πrh:

sa = 2πr² + 2πrh
sa = 2π(6²) + 2π(6 x 1)
sa = 2π(36) + 2π(6)
sa = (2 x 36)π + (2 x 6)π
sa = 72π + 12π
sa = 84π

For this diagram, the Pythagorean theorem states that b² = ?

47% Answer Correctly

	c² + a²
	c - a
	c² - a²
	a² - c²

Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c²) is equal to the sum of the two perpendicular sides squared (a² + b²): c²= a² + b² or, solved for c, \(c = \sqrt{a + b}\)