When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8a - 9a = -9a - 3z + 1 for a in terms of z.
| 2\(\frac{3}{5}\)z - 1\(\frac{3}{5}\) | |
| \(\frac{2}{5}\)z - \(\frac{4}{5}\) | |
| -\(\frac{1}{3}\)z + \(\frac{2}{3}\) | |
| 6z + 1 |