When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - c = c - 4z - 1 for c in terms of z.
| \(\frac{1}{13}\)z - \(\frac{3}{13}\) | |
| z + \(\frac{1}{5}\) | |
| -1\(\frac{1}{2}\)z - \(\frac{1}{2}\) | |
| 3z + 3 |