| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.84 |
| Score | 0% | 57% |
On this circle, a line segment connecting point A to point D is called:
diameter |
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chord |
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radius |
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circumference |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Which of the following is not true about both rectangles and squares?
all interior angles are right angles |
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the lengths of all sides are equal |
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the area is length x width |
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the perimeter is the sum of the lengths of all four sides |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
If side a = 2, side b = 3, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{82} \) | |
| \( \sqrt{10} \) | |
| \( \sqrt{52} \) | |
| \( \sqrt{13} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 22 + 32
c2 = 4 + 9
c2 = 13
c = \( \sqrt{13} \)
If a = c = 1, b = d = 7, what is the area of this rectangle?
| 54 | |
| 42 | |
| 7 | |
| 1 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 1 x 7
a = 7
Solve 2a - 3a = 4a - 2z - 5 for a in terms of z.
| -\(\frac{1}{2}\)z + 2\(\frac{1}{2}\) | |
| -\(\frac{2}{7}\)z + 1 | |
| -3\(\frac{1}{2}\)z + \(\frac{1}{2}\) | |
| z - 3 |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
2a - 3z = 4a - 2z - 5
2a = 4a - 2z - 5 + 3z
2a - 4a = -2z - 5 + 3z
-2a = z - 5
a = \( \frac{z - 5}{-2} \)
a = \( \frac{z}{-2} \) + \( \frac{-5}{-2} \)
a = -\(\frac{1}{2}\)z + 2\(\frac{1}{2}\)