ASVAB Math Knowledge Practice Test 30327 Results

Your Results Global Average
Questions 5 5
Correct 0 2.70
Score 0% 54%

Review

1

Solve for b:
b2 - 25 = 0

58% Answer Correctly
-1 or -4
4 or -1
5 or -5
7 or -9

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

b2 - 25 = 0
(b - 5)(b + 5) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 5) or (b + 5) must equal zero:

If (b - 5) = 0, b must equal 5
If (b + 5) = 0, b must equal -5

So the solution is that b = 5 or -5


2

Simplify (y - 5)(y - 1)

63% Answer Correctly
y2 - 4y - 5
y2 - 6y + 5
y2 + 4y - 5
y2 + 6y + 5

Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:

(y - 5)(y - 1)
(y x y) + (y x -1) + (-5 x y) + (-5 x -1)
y2 - y - 5y + 5
y2 - 6y + 5


3

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

chord

radius

circumference

diameter


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


4

If b = 9 and x = -4, what is the value of -b(b - x)?

68% Answer Correctly
-117
40
-32
-12

Solution

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

-b(b - x)
-1(9)(9 + 4)
-1(9)(13)
(-9)(13)
-117


5

Solve 8b - 7b = 5b - 6x + 8 for b in terms of x.

34% Answer Correctly
-x + 1
\(\frac{1}{3}\)x + 2\(\frac{2}{3}\)
-\(\frac{3}{10}\)x + \(\frac{1}{5}\)
-\(\frac{1}{5}\)x + \(\frac{3}{5}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

8b - 7x = 5b - 6x + 8
8b = 5b - 6x + 8 + 7x
8b - 5b = -6x + 8 + 7x
3b = x + 8
b = \( \frac{x + 8}{3} \)
b = \( \frac{x}{3} \) + \( \frac{8}{3} \)
b = \(\frac{1}{3}\)x + 2\(\frac{2}{3}\)