ASVAB Math Knowledge Practice Test 303520 Results

Your Results Global Average
Questions 5 5
Correct 0 3.22
Score 0% 64%

Review

1

Find the value of a:
6a + x = -5
-a - 2x = 4

42% Answer Correctly
-2\(\frac{11}{14}\)
2\(\frac{2}{23}\)
1\(\frac{3}{7}\)
-\(\frac{6}{11}\)

Solution

You need to find the value of a so solve the first equation in terms of x:

6a + x = -5
x = -5 - 6a

then substitute the result (-5 - 6a) into the second equation:

-a - 2(-5 - 6a) = 4
-a + (-2 x -5) + (-2 x -6a) = 4
-a + 10 + 12a = 4
-a + 12a = 4 - 10
11a = -6
a = \( \frac{-6}{11} \)
a = -\(\frac{6}{11}\)


2

The formula for the area of a circle is which of the following?

78% Answer Correctly

a = π d2

a = π r2

a = π d

a = π r


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


3

The endpoints of this line segment are at (-2, 5) and (2, 1). What is the slope of this line?

46% Answer Correctly
-3
-1
1
-2

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 5) and (2, 1) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(1.0) - (5.0)}{(2) - (-2)} \) = \( \frac{-4}{4} \)
m = -1


4

If the area of this square is 4, what is the length of one of the diagonals?

69% Answer Correctly
7\( \sqrt{2} \)
8\( \sqrt{2} \)
6\( \sqrt{2} \)
2\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)


5

Simplify 9a x 7b.

86% Answer Correctly
63\( \frac{a}{b} \)
63\( \frac{b}{a} \)
63a2b2
63ab

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

9a x 7b = (9 x 7) (a x b) = 63ab