ASVAB Math Knowledge Practice Test 304277 Results

Your Results Global Average
Questions 5 5
Correct 0 3.49
Score 0% 70%

Review

1

This diagram represents two parallel lines with a transversal. If w° = 32, what is the value of x°?

73% Answer Correctly
141
149
148
15

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with w° = 32, the value of x° is 148.


2

Simplify (6a)(5ab) + (9a2)(7b).

65% Answer Correctly
-33a2b
93a2b
93ab2
33ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(5ab) + (9a2)(7b)
(6 x 5)(a x a x b) + (9 x 7)(a2 x b)
(30)(a1+1 x b) + (63)(a2b)
30a2b + 63a2b
93a2b


3

A cylinder with a radius (r) and a height (h) has a surface area of:

54% Answer Correctly

π r2h2

2(π r2) + 2π rh

π r2h

4π r2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


4

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

91% Answer Correctly

exponents

pairs

division

addition


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


5

If side a = 6, side b = 4, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{85} \)
\( \sqrt{162} \)
\( \sqrt{52} \)
\( \sqrt{74} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 62 + 42
c2 = 36 + 16
c2 = 52
c = \( \sqrt{52} \)