| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.04 |
| Score | 0% | 61% |
If a = c = 6, b = d = 5, and the blue angle = 56°, what is the area of this parallelogram?
| 30 | |
| 5 | |
| 21 | |
| 72 |
The area of a parallelogram is equal to its length x width:
a = l x w
a = a x b
a = 6 x 5
a = 30
Simplify (2a)(8ab) + (8a2)(9b).
| 56ab2 | |
| 88ab2 | |
| 56a2b | |
| 88a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(2a)(8ab) + (8a2)(9b)
(2 x 8)(a x a x b) + (8 x 9)(a2 x b)
(16)(a1+1 x b) + (72)(a2b)
16a2b + 72a2b
88a2b
Which of the following is not true about both rectangles and squares?
the perimeter is the sum of the lengths of all four sides |
|
all interior angles are right angles |
|
the area is length x width |
|
the lengths of all sides are equal |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
If b = 7 and y = -4, what is the value of 4b(b - y)?
| 308 | |
| 36 | |
| -416 | |
| 120 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
4b(b - y)
4(7)(7 + 4)
4(7)(11)
(28)(11)
308
Solve for x:
9x + 2 < \( \frac{x}{-3} \)
| x < -1\(\frac{1}{34}\) | |
| x < \(\frac{16}{35}\) | |
| x < 2\(\frac{2}{13}\) | |
| x < -\(\frac{3}{14}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
9x + 2 < \( \frac{x}{-3} \)
-3 x (9x + 2) < x
(-3 x 9x) + (-3 x 2) < x
-27x - 6 < x
-27x - 6 - x < 0
-27x - x < 6
-28x < 6
x < \( \frac{6}{-28} \)
x < -\(\frac{3}{14}\)