ASVAB Math Knowledge Practice Test 305593 Results

Your Results Global Average
Questions 5 5
Correct 0 3.04
Score 0% 61%

Review

1

If a = c = 6, b = d = 5, and the blue angle = 56°, what is the area of this parallelogram?

65% Answer Correctly
30
5
21
72

Solution

The area of a parallelogram is equal to its length x width:

a = l x w
a = a x b
a = 6 x 5
a = 30


2

Simplify (2a)(8ab) + (8a2)(9b).

65% Answer Correctly
56ab2
88ab2
56a2b
88a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(2a)(8ab) + (8a2)(9b)
(2 x 8)(a x a x b) + (8 x 9)(a2 x b)
(16)(a1+1 x b) + (72)(a2b)
16a2b + 72a2b
88a2b


3

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the perimeter is the sum of the lengths of all four sides

all interior angles are right angles

the area is length x width

the lengths of all sides are equal


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


4

If b = 7 and y = -4, what is the value of 4b(b - y)?

68% Answer Correctly
308
36
-416
120

Solution

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

4b(b - y)
4(7)(7 + 4)
4(7)(11)
(28)(11)
308


5

Solve for x:
9x + 2 < \( \frac{x}{-3} \)

44% Answer Correctly
x < -1\(\frac{1}{34}\)
x < \(\frac{16}{35}\)
x < 2\(\frac{2}{13}\)
x < -\(\frac{3}{14}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

9x + 2 < \( \frac{x}{-3} \)
-3 x (9x + 2) < x
(-3 x 9x) + (-3 x 2) < x
-27x - 6 < x
-27x - 6 - x < 0
-27x - x < 6
-28x < 6
x < \( \frac{6}{-28} \)
x < -\(\frac{3}{14}\)