When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2b - 6b = 3b + 4z + 2 for b in terms of z.
| -\(\frac{7}{12}\)z - \(\frac{1}{3}\) | |
| 1\(\frac{1}{6}\)z - \(\frac{1}{6}\) | |
| -\(\frac{1}{4}\)z - \(\frac{7}{12}\) | |
| -10z - 2 |