When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -9c + 5c = -5c - z + 6 for c in terms of z.
| 1\(\frac{1}{2}\)z - 1\(\frac{1}{2}\) | |
| -4\(\frac{2}{3}\)z + 1 | |
| \(\frac{1}{5}\)z - \(\frac{1}{5}\) | |
| z + 2 |