When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c - 3c = 9c + 4y + 5 for c in terms of y.
| -\(\frac{4}{9}\)y - 1 | |
| -2y - 2 | |
| -1\(\frac{2}{5}\)y - 1 | |
| -\(\frac{3}{13}\)y + \(\frac{3}{13}\) |