ASVAB Math Knowledge Practice Test 310427

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve b + 6b = 6b + 7y - 7 for b in terms of y.

-1\(\frac{1}{5}\)y - 1\(\frac{1}{5}\)
-\(\frac{3}{4}\)y - \(\frac{1}{3}\)
-\(\frac{1}{5}\)y + 1\(\frac{2}{5}\)
\(\frac{5}{8}\)y + \(\frac{1}{16}\)