ASVAB Math Knowledge Practice Test 310427

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve a + 6a = 6a + 7z - 7 for a in terms of z.

-1\(\frac{1}{5}\)z - 1\(\frac{1}{5}\)
-\(\frac{3}{4}\)z - \(\frac{1}{3}\)
-\(\frac{1}{5}\)z + 1\(\frac{2}{5}\)
\(\frac{5}{8}\)z + \(\frac{1}{16}\)