When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -3c + 4c = 2c - 6z - 6 for c in terms of z.
| 2z + 1\(\frac{1}{5}\) | |
| -\(\frac{1}{7}\)z + \(\frac{2}{7}\) | |
| 7\(\frac{1}{2}\)z - 1\(\frac{1}{2}\) | |
| 1\(\frac{3}{4}\)z - 2 |