ASVAB Math Knowledge Practice Test 310910

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6c - 8c = 2c - 9y - 4 for c in terms of y.

-\(\frac{1}{4}\)y - 1
1\(\frac{1}{5}\)y + 1\(\frac{4}{5}\)
\(\frac{3}{13}\)y + \(\frac{1}{13}\)
1\(\frac{2}{5}\)y - \(\frac{1}{5}\)