ASVAB Math Knowledge Practice Test 31118

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 5b + b = 2b + 4z - 9 for b in terms of z.

-2z - \(\frac{4}{5}\)
-1\(\frac{3}{5}\)z - 1\(\frac{4}{5}\)
z - 3
-\(\frac{3}{5}\)z + 1\(\frac{2}{5}\)