ASVAB Math Knowledge Practice Test 311682

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3b + 4b = 5b + 5y + 2 for b in terms of y.

-4y + 1\(\frac{2}{3}\)
-y + 1
-\(\frac{1}{2}\)y - 1
2y + 4