ASVAB Math Knowledge Practice Test 311888

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -b - 5b = 6b + 7z + 3 for b in terms of z.

\(\frac{3}{13}\)z - \(\frac{4}{13}\)
-\(\frac{1}{4}\)z - \(\frac{1}{3}\)
-1\(\frac{5}{7}\)z - \(\frac{3}{7}\)
-2\(\frac{4}{5}\)z - 1\(\frac{4}{5}\)