ASVAB Math Knowledge Practice Test 312012 Results

Your Results Global Average
Questions 5 5
Correct 0 2.92
Score 0% 58%

Review

1

On this circle, line segment AB is the:

70% Answer Correctly

circumference

diameter

radius

chord


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


2

The endpoints of this line segment are at (-2, -8) and (2, 4). What is the slope-intercept equation for this line?

41% Answer Correctly
y = -1\(\frac{1}{2}\)x + 3
y = \(\frac{1}{2}\)x + 2
y = -2\(\frac{1}{2}\)x + 1
y = 3x - 2

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -2. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -8) and (2, 4) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(4.0) - (-8.0)}{(2) - (-2)} \) = \( \frac{12}{4} \)
m = 3

Plugging these values into the slope-intercept equation:

y = 3x - 2


3

A cylinder with a radius (r) and a height (h) has a surface area of:

52% Answer Correctly

4π r2

2(π r2) + 2π rh

π r2h

π r2h2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


4

What is the circumference of a circle with a diameter of 6?

70% Answer Correctly
11π
6π
24π
30π

Solution

The formula for circumference is circle diameter x π:

c = πd
c = 6π


5

Solve for z:
-5z + 3 = -6 + 9z

58% Answer Correctly
\(\frac{9}{14}\)
1\(\frac{1}{7}\)
1\(\frac{1}{3}\)
-1\(\frac{1}{2}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-5z + 3 = -6 + 9z
-5z = -6 + 9z - 3
-5z - 9z = -6 - 3
-14z = -9
z = \( \frac{-9}{-14} \)
z = \(\frac{9}{14}\)