When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c - 3c = 8c + 2y - 9 for c in terms of y.
| \(\frac{6}{11}\)y - \(\frac{6}{11}\) | |
| -1\(\frac{1}{4}\)y + 2\(\frac{1}{4}\) | |
| -2y + \(\frac{3}{5}\) | |
| 1\(\frac{1}{2}\)y + \(\frac{2}{3}\) |