When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c - 6c = 6c + 2z - 5 for c in terms of z.
| \(\frac{3}{5}\)z - \(\frac{3}{5}\) | |
| \(\frac{2}{9}\)z - \(\frac{2}{3}\) | |
| 4z - 2\(\frac{1}{2}\) | |
| 1\(\frac{1}{3}\)z - 2\(\frac{2}{3}\) |