ASVAB Math Knowledge Practice Test 312613

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4c - 3c = -6c + 4y - 6 for c in terms of y.

-y + \(\frac{1}{3}\)
\(\frac{7}{10}\)y - \(\frac{3}{5}\)
-2y + \(\frac{1}{3}\)
3y + 3