| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.42 |
| Score | 0% | 68% |
Which of the following is not required to define the slope-intercept equation for a line?
x-intercept |
|
slope |
|
\({\Delta y \over \Delta x}\) |
|
y-intercept |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.
If a = 2, b = 5, c = 8, and d = 7, what is the perimeter of this quadrilateral?
| 21 | |
| 27 | |
| 22 | |
| 9 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 2 + 5 + 8 + 7
p = 22
If side x = 7cm, side y = 11cm, and side z = 10cm what is the perimeter of this triangle?
| 34cm | |
| 28cm | |
| 25cm | |
| 26cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 7cm + 11cm + 10cm = 28cm
What is 8a + 2a?
| 10a2 | |
| 6 | |
| 16a | |
| 10a |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
8a + 2a = 10a
Solve for z:
z2 + z - 14 = -5z + 2
| 2 or -8 | |
| 5 or -7 | |
| -5 or -7 | |
| 2 or -9 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
z2 + z - 14 = -5z + 2
z2 + z - 14 - 2 = -5z
z2 + z + 5z - 16 = 0
z2 + 6z - 16 = 0
Next, factor the quadratic equation:
z2 + 6z - 16 = 0
(z - 2)(z + 8) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 2) or (z + 8) must equal zero:
If (z - 2) = 0, z must equal 2
If (z + 8) = 0, z must equal -8
So the solution is that z = 2 or -8